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 Post subject: Exam Plus Tiffins Paper
PostPosted: Fri Aug 30, 2019 10:42 am 
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Question 45.

5 Bangs make a Bing and 8 Bings make 3 Bongs.
Jon has 7 Bangs, 3 Bings and 9 Bongs.
If he changes all of his Bings and Bongs to Bangs, how many Bangs will Jon
have altogether?

This is how I worked out the answer:

1. you have to work backwards so 3 Bongs ake 8 Bings therefore 9 Bongs will make 24 Bings.
2. Now add the 3 Bings to the 24 Bings = 27 Bings.
3.Now 1 Bing = 5 Bongs so 27 * 5 = 135 Bangs
4.You have 7 Bangs on its own so add to 135 Bnags = 135 + 7 = 142 Bangs altogether.

Please- is this method to the answer correct?


Last edited by Londoner247363 on Fri Aug 30, 2019 11:53 am, edited 1 time in total.

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PostPosted: Fri Aug 30, 2019 11:50 am 
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Joined: Wed Jan 18, 2012 11:41 am
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Location: Essex
Londoner247363 wrote:
Question 45.

5 Bangs make a Bing and 8 Bings make 3 Bongs.
Jon has 7 Bangs, 3 Bings and 9 Bongs.
If he changes all of his Bings and Bongs to Bangs, how many Bangs will Jon
have altogether?

Can anyone help me with with question?


Start at the end and work backwards?

9 Bongs = 3 lots of '3 Bongs'
'3 Bongs' = 8 Bings
3 lots of 8 Bings = ## Bings
Add the 3 Bings also mentioned, = ??
Each Bing = 5 Bangs
So the number of Bangs Jon has is the ?? Bings, times 5, plus the 7 Bangs also mentioned
etc...

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PostPosted: Fri Aug 30, 2019 11:54 am 
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Joined: Wed Jan 18, 2012 11:41 am
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Location: Essex
Or short circuit it a bit; each 3 Bongs is (8x5 =) 40 Bangs, etc

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Outside of a dog, a book is a man's best friend. Inside of a dog it's too dark to read.Groucho Marx


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 Post subject: ToadMum
PostPosted: Fri Aug 30, 2019 11:54 am 
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Joined: Fri Aug 30, 2019 10:08 am
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Thank you


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