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PostPosted: Sun Aug 19, 2018 8:08 am 
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Joined: Sat Oct 14, 2017 12:29 pm
Posts: 25
The coordinates of the 4 vertices of a quadrilateral are:
(a–3 , b) (a , b) (a–3 , b + 2) (a , b + 2)
What shape is this?
A kite
B parallelogram
C square
D rectangle
E trapezium


can anyone help me to solve this question please. Thanks in advance


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PostPosted: Sun Aug 19, 2018 9:25 am 
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I would suggest plotting it. Choose a point to be (a,b) [select actual coords if you need to, say (4, 4)] then plot. Post again if you need another hint.


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PostPosted: Fri Aug 31, 2018 10:28 pm 
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Let origin be the coordinates (a, b) and add 2 and take away 3 so the shape would be a triangle.


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PostPosted: Tue Oct 09, 2018 10:00 am 
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Noreen Tousif wrote:
Let origin be the coordinates (a, b) and add 2 and take away 3 so the shape would be a rectangle.


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PostPosted: Tue Oct 09, 2018 10:18 am 
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I deliberately did not choose the origin as that gives negative co-ordinates.

How did you get a triangle from 4 points?


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PostPosted: Tue Oct 09, 2018 10:45 am 
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You can choose any values to (a, b), but if you choose smartly, it makes life easy. For example I choose a=3, b=0
It gives (0, 0) (3, 0) (0, 2) and (3, 2) which is a rectangle.


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PostPosted: Tue Oct 09, 2018 10:53 am 
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If you look at the X co ordinates two points lie on the same X co ordinate(a) and only differ in the Y co ordinate by 2 units. (b and b+2)
Similarly the remaining points have same X Co ordinate (a-3) and differ in y co ordinates by 2 units. (b and b+2)
Hence its a rectangle


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PostPosted: Tue Oct 09, 2018 11:07 am 
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Please note this question and my first response was posted two months ago ... we usually just try to give a hint and not the answer as that will not help with another question of a similar type.


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