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Exam Plus Tiffins Paper http://www2.elevenplusexams.co.uk/forum/11plus/viewtopic.php?f=2&t=58673 
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Author:  Londoner247363 [ Fri Aug 30, 2019 10:42 am ] 
Post subject:  Exam Plus Tiffins Paper 
Question 45. 5 Bangs make a Bing and 8 Bings make 3 Bongs. Jon has 7 Bangs, 3 Bings and 9 Bongs. If he changes all of his Bings and Bongs to Bangs, how many Bangs will Jon have altogether? This is how I worked out the answer: 1. you have to work backwards so 3 Bongs ake 8 Bings therefore 9 Bongs will make 24 Bings. 2. Now add the 3 Bings to the 24 Bings = 27 Bings. 3.Now 1 Bing = 5 Bongs so 27 * 5 = 135 Bangs 4.You have 7 Bangs on its own so add to 135 Bnags = 135 + 7 = 142 Bangs altogether. Please is this method to the answer correct? 
Author:  ToadMum [ Fri Aug 30, 2019 11:50 am ] 
Post subject:  Re: Exam Plus Tiffins Paper 
Londoner247363 wrote: Question 45. 5 Bangs make a Bing and 8 Bings make 3 Bongs. Jon has 7 Bangs, 3 Bings and 9 Bongs. If he changes all of his Bings and Bongs to Bangs, how many Bangs will Jon have altogether? Can anyone help me with with question? Start at the end and work backwards? 9 Bongs = 3 lots of '3 Bongs' '3 Bongs' = 8 Bings 3 lots of 8 Bings = ## Bings Add the 3 Bings also mentioned, = ?? Each Bing = 5 Bangs So the number of Bangs Jon has is the ?? Bings, times 5, plus the 7 Bangs also mentioned etc... 
Author:  ToadMum [ Fri Aug 30, 2019 11:54 am ] 
Post subject:  Re: Exam Plus Tiffins Paper 
Or short circuit it a bit; each 3 Bongs is (8x5 =) 40 Bangs, etc 
Author:  Londoner247363 [ Fri Aug 30, 2019 11:54 am ] 
Post subject:  ToadMum 
Thank you 
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